C=-17x-1x^2

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Solution for C=-17x-1x^2 equation:



=-17C-1C^2
We move all terms to the left:
-(-17C-1C^2)=0
We get rid of parentheses
1C^2+17C=0
We add all the numbers together, and all the variables
C^2+17C=0
a = 1; b = 17; c = 0;
Δ = b2-4ac
Δ = 172-4·1·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$C_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$C_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$C_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-17}{2*1}=\frac{-34}{2} =-17 $
$C_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+17}{2*1}=\frac{0}{2} =0 $

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